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((ln(0.5*x))^2)'The calculation above is a derivative of the function f (x)
2*(ln(0.5*x))^(2-1)*(ln(0.5*x))'
2*(ln(0.5*x))^(2-1)*(1/(0.5*x))*(0.5*x)'
2*(ln(0.5*x))^(2-1)*(1/(0.5*x))*((0.5)'*x+0.5*(x)')
2*(ln(0.5*x))^(2-1)*(1/(0.5*x))*(0*x+0.5*(x)')
2*(ln(0.5*x))^(2-1)*(1/(0.5*x))*(0*x+0.5*1)
2*(ln(0.5*x))^(2-1)*x^-1
2*x^-1*ln(0.5*x)
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